Log in to add a comment

## Answers

therefore it is in the form p/q where p and q are co prime numbers

3√2=p/q

√2 = p/3q

therefore l.h.s. is irrational no. and rhs is rational no.

but it is a contradiction

therefore our supposition is wrong

therefore it is a irrational number

The Brainliest Answer!

*let us take contradiction that 3√2 is rational number.*

*so if 3√2 is a rational number then***√**

*let 3√2=a/b,where a and b are co primes*

then

3then

3

**√**

*2=a/b*

*2=a/3b*

*here in the R.H.S side*

that is a/3b is a rational number but in the L.H.S side√2that is a/3b is a rational number but in the L.H.S side

**is irratioanal**

so 3

so 3

*√2*

*is a irrational number..................hope it helped u:))))))*