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## Answers

note that * means multiply

the above implies that

I = (A*adj(A)) / det(A) and I = (adj(A)*A) / det(A)

From above, we can say that det(A)I = A*adj(A) and det(A)I = adj(A)*A, then

A*adj(A) = adj(A)*A= det(A)*I

-(3) raies to power 1 + 1 will be ans because i = j

so we can say that ans will be 3