# Solve - a) 2m - 3 = 3/10 (5m-12) b) 6 (3a+2) - 5 (6a-1) = 3 (a-8) - 7 (5a-6) +9a c) 9x+7/2 - (x-(x-2/7) ) = 36 d) 2 (m-2) - 3 (m-3) = 5 (m-5) - 4 (m-8)

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by Sana06
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2015-05-16T15:21:53+05:30
a. 2m-3 = 3/10(5m-12)
2m-3 = 15m-36/10
10(2m-3) = 15m-36
20m-30 = 15m-36
20m - 15m = 30-36
5m = -6
m = -6/5

b.  6 (3a+2) - 5 (6a-1) = 3 (a-8) - 7 (5a-6) +9a
18a+12-30a+5 = 3a-24-35a+42+9a
-12a+17 = -23a+18
23a-12a = 18-17
11a = 1
a = 1/11

c. 9x+7/2 - (x-(x-2/7) ) = 36
[9x(2)+7] / 2 - (x-([7x-2/7)) = 36
[18x+7] / 2 -  (x-7x+2/7) = 36
[18x+7] / 2 -  (-6x+2/7) = 36
lcm of 2, 7 is 14
[18x(7) +7(7) +6x(2)-2(2)] / 7 = 36
126x+44+12x-4/7 = 36
138x+40=36×7
138x = 252 - 40
138x = 212
x = 106/69

d. 2 (m-2) - 3 (m-3) = 5 (m-5) - 4 (m-8)
2m-4-3m+9 = 5m-25-4m+32
5-m = m + 7
m+m = 5-7
2m = -2
m = -1

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2015-05-16T15:34:07+05:30

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6 (3 a + 2)  -  5 (6 a - 1) =  3 ( a  - 8) - 7 ( 5 a - 6) + 9 a
18 a + 12  - 30 a + 5 = 3 a - 24 - 35 a + 42 + 9 a
- 12 a + 17 = - 23 a + 18
23 a - 12 a = 18 - 17
11 a = 1
a =  1 / 11

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here it is not clear  if the  2 in denominator, has numerator  7  or  9 x + 7 ??
same way,  it is x-2  or  2 in the numerator for  denominator 7 ?

case 1:

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case 2:

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