# (i)in a simple attwood machine 2 unequal masses m1 and m2 are connected by a string going over a clamped light smooth pulley.in typical arrangement m1=300g and m2=600g *thye distance travelled by the first block in first 2 seconds is (the attachemtn is valid for first uestion only) *the tension in the string is *draw fbds os m1 ,m2 and pulley(ii)look at second attachement of integer questions(iii)2 masses m and M respectively are connected by a light string passing over a smooth pulley when set free m moves up by 1.4 m in 2 secthe ratio of m/M is

1
by rajusetu

2015-05-18T02:28:34+05:30

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Equations of motion or dynamics for the diagram/question are:

T - m1 g = m1 a
m2 g - T = m2 a

=>  a = (m2 - m1) g / (m1 + m2)
=  (600 - 300) * 10 / (600 + 300) = 10/3 m/sec/sec

If  u = 0 ,  and  t = 2 sec.
s = u t + 1/2  a t^2 = 20/3 meters
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solving the first two equations
T = 2 m1 * m2 * g / (m1 + m2)
= 2 * 600 * 300 * 10 / 900 = 4 000 newtons
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iii)
s = 1.4 meters
t = 2 sec.
u = 0.
s = ut + 1/2 a t^2  =>
a = 2 * 1.4 / 4 = 0.7 meters/sec/sec

a  =  (m2 - m1) g / ( m1 + m2)
=  (m2/m1 - 1) g / (m2 / m1  + 1 )

=>    m2/m1 + 1 =  (m2/m1 -1 )  * g/a
m2/m1  [g/a - 1]  =  1 + g/a
m2 / m1  =  (a + g) / (g - a)

m2 / m1  =  (10 + 0.7) / (10 - 0.7)  = 10.7 / 9.3

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Block B is on top of block  A.

Block A has mass    m.      So its acceleration =  10 Newtons / m
It moves by 20 cm  before block B falls.
u = 0

s = u t + 1/2 a t^2

20 cm = 0 + 1/2 * (10/m) * t^2
find t from this by substituting the value of m.
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In the question Is the rod AB is resting  on a surface  OB ??

it is not clear what  OB is..  is there friction at the points  A and B ??

is it possible that n = 1  or  n = 1/2 ??

you should solve one with friction and one without friction
plaese3 solve it by using 2 cases
i clicked on blue button.........................
sir............