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Let the North be represented by Y axis.  The when the car turns left, it moves along the -ve x axis, towards West.

Let \vec{v1} = 50 \hat{j}\ kmph\ \ \ and,\ \vec{v2} = -50 \hat{i}\ kmph

Change in velocity is = \vec{v2}-\vec{v1}=-50\hat{i}-50\hat{j}\ kmph

Magnitude of change in velocity=\sqrt{50^2+50^2}=50\sqrt{2}

Direction of the change in velocity = South west , 45 deg. from South towards West.

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