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I think there are four optical isomers for 2,3 - dibromobutane.
The structure is :
CH₃ - *CHBr - *CHBr - CH₃

As we can see, there are two asymmetrical carbon atoms(denoted with ' * ' ).

Every asymmetrical carbon atom exhibits one leavo and one dextro rotatory isomerisms.

As there are two asymmetrical carbon atoms, there are a total of four optical isomers for 2,3 - dibromobutane
1 5 1
Please let me know if my answer is wrong! I'm not 100% sure actually!