The front and back ends of a train moving with uniform aceleration pass a stationary observer with velocities 'u' and 'v' respectively. The velocity of the middle point of the train while passing the observer would be :
(1) √(u² + v²)
(2)√(u² + v²)/2
(3)(u² + v²)/2
(4)(u+v)/2

2

Answers

2015-05-21T07:47:42+05:30
The answer is option (4) (u + v)/2
0
2015-05-21T08:36:43+05:30
the middle point of the train while passing the observer would be :

(4)(u+v)/2
0