# A ship sends out ultrasound that returns from the seabed and is detected after 3.42 s. If the speed of ultrasound through seawater is 1531 m/s, what is the distance of the seabed from the ship? NCERT Class IX Sciences - Main Course Book Chapter 12. Sound

2
by NandRamesh286

2015-05-21T14:01:01+05:30
We know that speed = distance / time
given
d=?
s=1531m/s
now half of 3.42 that is:
3.42/2=1.71\
so (time) t=1.71s

therefore

distance =speed * time
d=s*t
d=1531*1.71
d=2.618.01
d=2.6 km
2015-05-21T14:40:01+05:30

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Distance =  speed  *  time duration
=  1, 531 * 3.42 =  5, 236.02 meters

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but the distance is asked from the boat to the sea bed .. would u clarify this to me.
speed given is that of ultrasonic sound in sea water. The distance travelled by the wave is twice the depth of sea water, as sound travels down and again up. So distance = 1,531 * 3.42 /2 = 2, 618.01 meters or 2.618 km.
sorry for the error