A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

NCERT Class IX
Sciences - Main Course Book

Chapter 10. Gravitation

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Answers

2015-05-21T17:49:23+05:30
Maximum height reached by the stone(H) = u²/2g
                                [where u = initial velocity and g = gravitational acceleration.]
                                                         =40²/(2×10).
                                                         = 80 m.
Net displacement = 0 m.[ Initial position coincides with final position.]
Total distance covered = (2×H) = (2×80) = 160 m. (Ans.)
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