# A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled. NCERT Class IX Sciences - Main Course Book Chapter 8. Motion

2
by gotamaSing

2015-05-21T21:10:58+05:30
Given,

Initial velocity(u)="0m/s"
Accelaration(a)="0,1m/s-2"
Time="2 mins=60*2=120 secs"
Final velocity=?

v=u+at
v=0+(0.1)120
v=0+12
v=12m/s
i.e
Final Velocity="12m/s"
Distance(s)=v(v)-u(u)=2a
s=144-0=2(0.1)
s=144=0.2
s=1440=2
s=720m

Therefore,
(a)=12m/s
(b)=720m
2015-05-21T23:11:42+05:30

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U = 0,      a = 0.1 m/sec²        t = 120 sec = 2minutes

equation of motion :  v = u + a t = 0 + 0.10 * 120 = 12 m/sec

s = u t + 1/2 a t² = 0 + 1/2 * 0.10 * 120² = 720 meters