# Two resistors of 10 ohms and 15 ohms are connected in series to a battery of 6 v . how can the value of the current passing through them be compared?

2
by ET10400

2015-05-23T11:30:33+05:30
FIRST WE FIND TOTAL RESISTANCE
IN SERIES,        TOTAL R=R₁+R₂.........RN
HERE,                   TOTAL RESISTANCE=10Ω+15Ω=25Ω
ALSO WE KNOW THAT      Δ V=IR (ΔV IS POTENTIAL DIFFERENCE)
HERE                I=?
R=25Ω
Δ V=6 volts
PUTTING IN THE EQUATION
6=I×25
I=6/25À

I am sorry ...i have got one doubt ....but in question it is asked about "how can the values of current passing through them compared?" so my doubt is ..that. i have understood what u have done..but i still don't get the comparing part...#Kshitijmanitiwari
2015-05-24T09:09:10+05:30
In a series connection
total resistance is equal to R=r1+r2+r3+r4+...............+rinfinity
total resistance offred by object             =10Ω+15Ω=25Ω
Change in potential diffrenece=IR
6=I×25
so I=6/25

I am sorry ...i have got one doubt ....but in question it is asked about "how can the values of current passing through them compared?" so my doubt is ..that. i have understood what u have done..but i still don't get the comparing part...#Rajusetu