#
) If a and b are the zeros of the quadratic polynomial

f(x)= x2-5x+4, find the value of (1/a + 1/b) –2a b

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f(x)= x2-5x+4, find the value of (1/a + 1/b) –2a b

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we have ab=4 and a+b =-5 Now simply substitute {-5/4}-2X4

=(-5/4)-8=-(37/4) will be the answer.

another way is also there, we can easily calculate a and b as -4 and -1. Now substitute this to the equation (1/a + 1/b) –2a b you will get same answer!

we have ab=4 and a+b =-5 Now simply substitute {-5/4}-2X4

=(-5/4)-8=-(37/4) will be the answer.

another way is also there, we can easily calculate a and b as -4 and -1. Now substitute this to the equation (1/a + 1/b) –2a b