# The vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, calculate the minimum inaccuracy in the measurement of distance.

1
Log in to add a comment

Log in to add a comment

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

The least count = 1/50.

so precision in measurements = 1/50 * 0.5 mm = 0.01 mm

so precision in measurements = 1/50 * 0.5 mm = 0.01 mm

49 main scale divisions = 49 * 0.5 mm = 24.5 mm.

50 Vernier scale divisions = 24.5 mm => each vernier scale division = 24.5/50 = 0.49 mm

the difference between the lengths of one main scale division and one vernier scale division = 0.50 - 0.49 mm = 0.01 mm.

This is the least count of the Vernier scale. When you measure the length of an object, the length is measurable up to an accuracy of 0.01 mm.

50 Vernier scale divisions = 24.5 mm => each vernier scale division = 24.5/50 = 0.49 mm

the difference between the lengths of one main scale division and one vernier scale division = 0.50 - 0.49 mm = 0.01 mm.

This is the least count of the Vernier scale. When you measure the length of an object, the length is measurable up to an accuracy of 0.01 mm.

Suppose we have an object of length 2.11 mm. We put that in the Vernier calipers. Then we read the vernier scale. That will match with the main scale at the 11th division... On the main scale it will read 15 divisions. It means 7.50 mm.. On the vernier scale 11 divisions means 11 * 0.49mm = 5.39 mm... Subtracting 5.39 mm from 7.50 mm , we get the length of the object as 2.11 mm.