# The sum of the present age of a father and a son is 54 years. 6 years back , the father's age was 2 years more than 4 times the age of the son at that time. Find their present ages?

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by aahtews

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by aahtews

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Answer :

Let Present age of Father (in Years)= x

and Present age of Son (in Years)= y

According to Question,

x + y = 54

or**x = 54 - y **---- **1st**

Before 6 years ,

Fathers age = x+6

Sons Age = y+6

x -6 = 4(y -6) + 2

or x - 6 = 4y - 24 + 2

x = 4y - 22 + 6

** x = 4y - 16**

Using Ist , we get

54 - y = 4y - 16

54 + 16 = 4y + y

70 = 5y

or**y = 14**

Substitute Value of y in Ist we get ,

x = 54 - 1**4**

x = 40

Hence Present age of Father = 40 years

and Present age of Son = 14 years

Hope This Helps You!!

Thank You!!

Let Present age of Father (in Years)= x

and Present age of Son (in Years)= y

According to Question,

x + y = 54

or

Before 6 years ,

Fathers age = x+6

Sons Age = y+6

x -6 = 4(y -6) + 2

or x - 6 = 4y - 24 + 2

x = 4y - 22 + 6

Using Ist , we get

54 - y = 4y - 16

54 + 16 = 4y + y

70 = 5y

or

Substitute Value of y in Ist we get ,

x = 40

Hence Present age of Father = 40 years

and Present age of Son = 14 years

Hope This Helps You!!

Thank You!!