Answers

2014-05-16T10:14:20+05:30
Formula for distance after n th second is,Sn=u+a(n-1/2)
where u-initial velocity,a-acceleration,n-nth second
here,                                                            
u=0 m/sec
a=0.9 m/s^2
n=6
=>Sn=0+0.9(6-1/2)
        =0.9(11/2)=4.95 m
hence,the distance of box is 4.95 m after 6 sec
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2014-05-16T16:19:16+05:30
S = ut + 1/2at^2
u = 0 , t = 6 seconds a = 0.9m/sec.^2
s = 0 + 1/2*0.9*36
s = 16.2meter
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