Answers

2015-05-26T23:41:40+05:30
80% of the volume of air contains oxygen
so volume of oxygen = 0.8 L
at STP 22.4 L of oxygen contains 6.023×10²³ molecules of O₂
so at STP 0.8  L of oxygen contains (6.023×10²³/22.4)=2.69 ×10²³ molecules of O₂
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