show that p square will leave remainder 1 when devided by 8, if p is an odd positive integer

1
by anjumum125

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show that p square will leave remainder 1 when devided by 8, if p is an odd positive integer

1
by anjumum125

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p^2 = 9 => 9/8 =>1+1/8

we will get remainder as 1

let us take p=5 then

p^2=25 => 25/8 => 3+1/8

we will get remainder as 1

and so on............