# A 8000 kg engine pulls a train of 5 wagons,,each of 2000 kg along a horizontal track .If the engine exerts a force of 40000 N and track offers a friction force of 5000 N, then calculate<(a) the net acceleration force(b) the acceleration of train and(c) the force of wagon 1 on wagon 2

2
by nickymane

• Brainly User
2014-05-17T11:02:05+05:30
Mass of the engine = 8000 kg
Mass of each wagon = 2000 kg,
Np. of wagons = 5
Total mass of train = 8000+2000×5= 18000 kg
Force, F = 40000 N
Track resistance , R = 5000 N
Total accelerating force = F −R =40000−5000=35000 N
Let acceleration = x m/s²
Acceleration , = Accelerating force / mass
x=35000/18000= 35/18=1.94 m/s²
Frictional resistance of 4 wagons = 5000×(2000×4)/18000 =2222 .22 N
Accelerating force on 4 wagons =2000×4×1.944 =15552 N
Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance
=2222 .22 +15552=17774.22 N
Total force required to produce acc
2014-05-17T11:23:00+05:30
Mass of the engine = 8000 kg
Mass of each wagon = 2000 kg,
Np. of wagons = 5
mass of total wagon=2000*5
=10000
Total mass of train = 8000+2000*5= 18000 kg
Force, F = 40000 N
Track resistance , R = 5000 N
Total accelerating force = F −R
=40000−5000
=35000 N
Let acceleration = y m/s²
Acceleration  = Accelerating force / mass
y=35000/18000
= 35/18
=1.94 m/s²
Frictional resistance of 4 wagons = 5000*(2000*4)/18000 =2222 .22 N
Accelerating force on 4 wagons =2000*4*1.944 =15552 N
Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance
=2222 .22 +15552=17774.22 N
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