# Questions Q1) an electron moving with the velocity of 5x 10( raised to the power 4) m/s enters into uniform electric field and acquires a uniform acceleration of 10 ( raised to the power 4) m/s ( raised to the power 2)in the direction of its initial velocity. CALCULATE (1) time in which the electron would acquire a velocity double of it's initial velocity. 2) how much distance would electron cover in this time. Q2) distance in covered (in cm) time object a object b object c 1st 20 20 20 2nd 20 36 60 3rd 20 24 100 4th 20 30 140 5th 20 48 180 answer the following Q1) which object is moving with constant speed and why? Q2) which object is moving with constant acceleration ? how much is acceleration? Q3) which object is moving with an irregular acceleration? Q4) How much distance does a,b,c, cover in 5 seconds.

1
by iza

2015-06-03T23:26:13+05:30
Q.1>  (1) u (initial velocity) = 5 × 10⁴ m/s        v (final velocity) = 10⁵ m/s
a (acceleration) = 10⁴ m/s²               t (time) = t (unknown)
v = u + at
100000 = 50000 + 10000×t
100000 - 50000 = 10000×t
50000 = 10000×t
t = 50000 / 10000 = 5 s
(2) s (distance) = (u + v) t / 2
= 5 (50000 + 100000) / 2
= 5×150000 / 2
= 750000 / 2
= 375000 m
= 3.75 × 10⁵ m    OR     375 km

Q.2> (1) Object A is moving at constant speed, as its distance covered is equal               at regular intervals of time.
(2) Object C is moving with a constant acceleration of 40 cm/s².
(3) Object B is moving with an irregular acceleration.
(4) Object A : 100 m
Object B : 158 m
Object C : 500 m
Thank youu sooo muchh. The answer was in need.....
You're welcome
There is one more question the new one can you also help me if it ispossible for you to solve