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Ten years ago a age was half of b if the

ratio of their present age is 3 ratio 4 what

will be the sum of their age

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ratio of their present age is 3 ratio 4 what

will be the sum of their age

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given ten years ago, a was half of b

=> 2(3x X 10) = (4x X 10)

=> 6x X 20 = 4x X 10

=> 2x = 10

=> x = 5

p=q/2

Now present (p+10)/(q+10) = 3/4

4(p+10) = 3(q+10)

4p+40 = 3q + 30

4p - 3q = 30 - 40

but we know that p = q/2 ⇒2p = q

2(2p) - 3q = -10

2q - 3q = -10

-q = -10

q = 10

the age of 'b' ten years ago was 'q' = 10

now present age of 'b' = q+10

= 10+10

= 20

ten years ago the age of 'a' is p=q/2 = 10/2 = 5

now present age of 'a' is p+10 = 5+10 = 15

therefore the sum of the ages of 'a' and 'b' is 20+15 = 35