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## Answers

If n! is defined as the product of all positive integers from 1 to n, then:

1! = 1*1 = 1

2! = 1*2 = 2

3! = 1*2*3 = 6

4! = 1*2*3*4 = 24

...

n! = 1*2*3*...*(n-2)*(n-1)*n

and so on.

Logically, n! can also be expressed n*(n-1)! .

Therefore, at n=1, using n! = n*(n-1)!

1! = 1*0!

which simplifies to 1 = 0 i have done it by my own