Answers

2015-06-05T09:44:08+05:30
X-a is a factor of  x^{6}-ax^{5}+x^{4}-ax^{3}+3x-a+2 .
Here, the degree of polynomial is = 6.So, this polynomial has 6 roots.
P(a) = 0 ( If we insert a in place of x we get 0 remainder , because a factor                          completely divides it divident )
x-a = 0
x = a
Now,
Insert x at the place of a.
so,
 x^{6}-ax^{5}+x^{4}-ax^{3}+3x-x+2 = 0
 x^{6}-x^{6}+x^{4}-x^{4}+3x-x+2 = 0
2a - 2 = 0
2a = 2
a =  \frac{2}{2}
a = 1
Therefore , first root is x - 1.

Now, to find second root divide x-1 by  x^{6}-ax^{5}+x^{4}-ax^{3}+3x-a+2
You will have a quotient.
Now, again insert x = a and find the value of a .
Whatever will be the value would be the value of a.

I hope it helps .







1 5 1
thanks for your answer it is very helpful for me