Answers

2015-06-05T13:11:53+05:30
The divisibility test for 8 is last 3 numbers of a number 
has to be divided by 8.so 120 is the smallest digit which is divisible by 
6 and 12.
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2015-06-05T13:15:32+05:30
Since for divisibility from 6 8 and 12 we have to find such no. which is divisible by 6,8 and 12. for 3 digit no. the minimum no. is 120
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