A baseball is popped straight up into the air and has a hang-time of 6.25s. Determine the height to which the ball rises before it reaches its peak.(Hint : the time to rise to the peak is one half the total hang time )

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we need either the mass or the initial and final velocities

Answers

The Brainliest Answer!
2015-06-07T11:54:47+05:30
At the maximum height of the ball, the velocity will be zero. This will also take half the total time, 3.125 s. 
Now use the equation... 
Δd = vf*t - 1/2at^2 

By setting the final time at the moment of the apex of the height, vf becomes 0. 
So the equation will become... 
Δd = - 1/2at^2 

The equation now resembles the change in height from the ground to the maximum height 

Δd = - 1/2at^2 = - 1/2 (-9.8 m/s^2) (3.125 s)^2 = 47.8 m
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