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Calculate the energy transferred when 2A current flows through a 10 ohm

resistor for 30 mins.

2
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resistor for 30 mins.

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V = 2 × 10 = 20 volts

We know, P = VI

P = 20 × 2 = 40W

We know, Power = Work/Time

⇒ Energy = Power × Time = 40 × 30 ×60 = 72000J = 72 KJ

V = IR

V = 2 × 10 = 20 volts

We know, P = VI

P = 20 × 2 = 40 Watts

We know, Power = Energy/Time

So, Energy = Power × Time = P x t = 40 × 30 × 60 = 72000Joules = 72 Kilo Joules