# In a country, 7/10 of the population are Chinese. 2/3 of the remainder are Malays and the rest are Indians. If there are 60,000 Indians, how many Chinese are there?

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Solution:

Let the total population of country = x

therefore , Chinese population in country = (7/10) *x

= 7x/10 .

therefore Remaining population of Country (People who are not chinese ) = total Population - chinese population

= x - 7/10 *x

= (10x - 7x )/10

= 3x/10

According to question ,

Malays are 2/3 or remaining population , hence

Malays people = (2/3)*(3x/10)

= x /5

rest of the remaining population is 60,000 Indians

3x/10 - x/5 = 60,000

(15x - 10x )/50 = 60 , 000

5x / 10 = 60000

x = 10 *60000 / 5

= 1200000

Therefore Total Population of country = 1,20,000

Hope U understand the Solution!