# The adjacent sides of a parallelogram are 20 m and 16 m. The distance between the shorter sides is 5 m. Find the area and the distance between the longer sides.

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by reishumwi

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by reishumwi

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Area = 16 * 5 = 20 * H => answer = 4 meters

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AB = 20 m

AC = 16 m AC is the shorter side.

The perpendicular distance between the shorter sides AC and BD = H1 = 5 m

Area of parallelogram ABCD = AC * H1 = 16 * 5 = 80 meter²

Let the perpendicular distance between the longer sides AB and CD = H2 meters

Area of ABCD is also = AB * H2 = 80 meters²

=> H2 = 80 / 20 = 4 meters.

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AB = 20 m

AC = 16 m AC is the shorter side.

The perpendicular distance between the shorter sides AC and BD = H1 = 5 m

Area of parallelogram ABCD = AC * H1 = 16 * 5 = 80 meter²

Let the perpendicular distance between the longer sides AB and CD = H2 meters

Area of ABCD is also = AB * H2 = 80 meters²

=> H2 = 80 / 20 = 4 meters.