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## Answers

xy = k --------------(2) are orthogonal to each other hence tangent on are orthogonal

differentiating both equation

2ydy/dx = 1

dy/dx = 1/2y let m1

xdy/dx + y = 0

dy/dx = -y/x let m2

for orthogonal

m1*m2 = -1

(-y/x)*(1/2y) = -1

x = 1/2

put x = 1/2 in (2) equation

y = 2k

put y = 2k & x = 1/2 in equation (1)

4k² = 1/2

8k² = 1 prove