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2015-06-12T20:51:19+05:30

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Given mass (M₁) = 50g
Temperature (T₁) = 20° C
Mass (M₂) = 50g
Temperature (T₂) = 20° C
By using the method of mixture ,
Final temperature (T) = (M₁T₁+M₂T₂)/M₁+M₂
                               = (50×20+50×20)/50+50
                                = 2000/100
                                = 20° C .

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2015-06-12T21:01:14+05:30

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Given mass m1 = 50 grams
Temperature T1 = 20° C
Mass M2 = 50g
Temperature T2 = 20° C
then, 
Final Temperature = M1T1 + M2T2 / M1+M2
                         = (50×20+50×20)/50+50
                                = 1000+1000/100
                                = 2000/100
                                = 20° C .
Therefore, Final Temperature T= 20° C

*Note: In the question, both masses and temperature are equal of same substance. So, when they keep in contact, no change can be seen sincce their temperatures are same. Hence although they keep in contact they attain thermal equilibrium wth the same Temperature i.e., 20° C
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hope it helps u..
hmm...
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nice!:))
:)) tysm tp sahu! lol