## Answers

now for inverse trio function

eg there is formula

sin^-1(sinx)=x

similarly

cot^-1(cot (pi/4-x))=pi/4-x

now

cot(pi/4-x)=(cosx+sinx)/(cosx-sinx)

so

Lhs=pi/4-x

LHS=RHS

now for inverse trio function

eg there is formula

sin^-1(sinx)=x

similarly

cot^-1(cot (pi/4-x))=pi/4-x

now

cot(pi/4-x)=(cosx+sinx)/(cosx-sinx)

so

Lhs=pi/4-x

LHS=RHS

I have typed it right ..

by the way its an Inverse trigo function (just saying :P )