# Q1) In a 100m track event the time taken by four runners is 10sec,10.2sec,10.4sec and 10.6sec.Find the ratio of their speed? Q2)In a 4x100m relay race total length is 200m and time taken by one particular group is 50.2s.What is the average velocity and average speed of that group? Q3)In a long jump event,the total path covered by an athlete is 10.6m.Is it distance or displacement?Why?Give reason for your answer?

2
by So234
In question no2 is the path a circle of a straight line

2015-06-13T17:45:01+05:30
Speed of 1st runner- distance/time 100/10 =10m/sec Speed of 2nd runner=distance/time = 100/10.2 =100×2/10=20m/sec Speed of 3rd runner=distance/time =100/10.4=100×4/10=40m/sec Speed of 4th runner =distance/time =100/10.6=100×6/10=60m/sec Now ratio 10/20/40/60 =10×1/20×1/40×1/60= 1:4800 ANSWER OF QUESTION 3 It is both distance as well as displacement Because in a game of long jump it is a strqight line to be covered So in a straight line distance and displacement is same. Therefore the given magnitude is distance as well as its displacement
2015-06-13T20:30:20+05:30
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=
we get
V₁=
V₁=10m/s

V₂=
V₂=9.8m/s

V₃=
V₃=9.61 m/s

V₄=
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43

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