Answers

2015-06-16T10:45:55+05:30
Sinθ = P/H ---------------1
cosθ = B/H --------------2

Now , LHS

sin²θ + cos²θ
from 1 and 2

 \frac{P^2}{H^2} + \frac{B^2}{H^2}

 \frac{P^2+B^2}{H^2}  -----------3

By Pythagoras theorem 
P² + B² = H²

Putting this in 3

 \frac{H^2}{H^2}
= 1

LHS = RHS

HENCE PROVED 
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