# A current of 1 ampere flows in series circuit contains an electric lamp and a conductor of 5 ohm when connected to a 10V battery. Calculate the resistance of the electric lamp. Now if a resistance of 10 ohm is connected in parallel with this series combination, what change in current flowing through 5 ohm conductor and potential difference across the lamp will take place? Give reason. Pleeeeeeeeeez help with above question! Need it very urgently, ASAP!!!

1
by manasviranjan

2015-06-16T13:07:00+05:30

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Part 1:
Let R be the resistance of the electric lamp. In series total resistance = 5 + R
I =
1 =
R = 5 ohm

Part 2:
Total Resistance =
I =
Current in each branch  = 2 / 2 = 1 Amp (since both branches have same resistances, current divides equally)

V across Lamp + conductor = 10 V
V acoess Lamp = I × R = 1 * 5 = 5 Volt

Thanxxxx so much! Means a ton! :)