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Solve only-38,42,43,45,47,48

1
by rajusetu

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Solve only-38,42,43,45,47,48

by rajusetu

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38. P V = n R T = (m/M) RT, d = m/V

P = (d / M) R T

find M = d R T / P

P = 764 mm * 13.6 * g , g = acceleration due to gravity

from M, using formulas for NO, N2O, NO2, NO3, N3O, N2O2... check which one matches.

42. P = 0.61 kPa = 0.61 * 1000 * N/m^2

P = density of Hg * acceleration due to gravity g * height of Hg column in barometer

height in meters Hg = h = P / [13.6 *1000 kg/m^3 * g in m/sec^2 ]

g = 9.81 m/sec^2 or 10 m/sec^2

height in mm = h * 1000

43. d1 = 6.095 gm/ml 1 torr = 1 atm / 760

P = 740 mm Hg

ie., height of mercury column is 740 mm in barometer..

P = density of liquid * g * height of liquid inside barometer tube

as pressure is same.. h is inversely proportional to density.

h1 d1 = h2 d2 => h2 = 13.6 * 740 / 6.095 mm

convert to cm..

45. V1, P1 are given..

P2 at 10 ft = 10 * (12 * 2.54 * 10) mm water + P1

P1 = 760 mm Hg

P2 = P1 + 10 * (12*25.4) * density of water/density of Hg mm Hg

= 760 + 120*25.4 * 1/13.6 mm Hg

P1 V1 = P2 V2

10 feet of water = 10* 12 * 25.4 /13.6 mm of Hg

47. m1 / m2 = 2.375/ 1.00 = M2 / 32 32 = molecular mass of O2..

which gas has molecular weight = M2 ? check..

48. m = 6.81 gm V = 1.16 * 10^4 L T = -23 C convert to kelvin

P V = m/M R T

P1 = m1 R T / (V1 * M)

convert P1 in dynes/cm^2 or N/m^2

m2 = P2 V1 M / (R T)

P2 = 4.0 * 10^-3 atm convert to N/m^2 or dynes/cm^2

So if V, T remain same... m is proportional to pressure.

answer m2 - m1..

P = (d / M) R T

find M = d R T / P

P = 764 mm * 13.6 * g , g = acceleration due to gravity

from M, using formulas for NO, N2O, NO2, NO3, N3O, N2O2... check which one matches.

42. P = 0.61 kPa = 0.61 * 1000 * N/m^2

P = density of Hg * acceleration due to gravity g * height of Hg column in barometer

height in meters Hg = h = P / [13.6 *1000 kg/m^3 * g in m/sec^2 ]

g = 9.81 m/sec^2 or 10 m/sec^2

height in mm = h * 1000

43. d1 = 6.095 gm/ml 1 torr = 1 atm / 760

P = 740 mm Hg

ie., height of mercury column is 740 mm in barometer..

P = density of liquid * g * height of liquid inside barometer tube

as pressure is same.. h is inversely proportional to density.

h1 d1 = h2 d2 => h2 = 13.6 * 740 / 6.095 mm

convert to cm..

45. V1, P1 are given..

P2 at 10 ft = 10 * (12 * 2.54 * 10) mm water + P1

P1 = 760 mm Hg

P2 = P1 + 10 * (12*25.4) * density of water/density of Hg mm Hg

= 760 + 120*25.4 * 1/13.6 mm Hg

P1 V1 = P2 V2

10 feet of water = 10* 12 * 25.4 /13.6 mm of Hg

47. m1 / m2 = 2.375/ 1.00 = M2 / 32 32 = molecular mass of O2..

which gas has molecular weight = M2 ? check..

48. m = 6.81 gm V = 1.16 * 10^4 L T = -23 C convert to kelvin

P V = m/M R T

P1 = m1 R T / (V1 * M)

convert P1 in dynes/cm^2 or N/m^2

m2 = P2 V1 M / (R T)

P2 = 4.0 * 10^-3 atm convert to N/m^2 or dynes/cm^2

So if V, T remain same... m is proportional to pressure.

answer m2 - m1..