Answers

2015-06-17T21:42:27+05:30
1 WAY IS THAT KEEP 1 W BALL THEN R BALL & SO ONE
2 WAY IS TO KEEP THE R BALLS AT THE TWO ENDS AND IN B/W  W BALLS
3,4,5,6 WAY IS BY KEEPING 1 R BALL AT THE END AND CHANGING THE OTHER R BALL'S POSITION IN SUCH A WAY THAT ATLEAST 1 W BALL IS IN B/W
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2015-06-18T01:42:51+05:30

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        1    W    2     W    3     W   4     W    5    W    6

Let the white balls W be arranged as above.  There are 6 slots in which red balls can be placed.    There are 3 red balls to place in any 3 of 6 slots.

So  the number of ways:   {}^6C_3  = 6 ! / (3! * 3!)
             = 20 ways.

1 5 1
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how come 3 factorial * 3 factorial in denominator ?
formula for combinations nCr
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