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2015-06-21T14:14:58+05:30

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From equation 1:
y=7- \sqrt{x}
Put this in the second equation:
x+ \sqrt{7- \sqrt{x} }  = 11
 \sqrt{7- \sqrt{x} } = 11-x \\ 7- \sqrt{x} =121+ x^{2} -22x \\ (x^2-22x+114)^2=x

If the above equation is solved, it will give x = 
 9.0000
14.2832
 12.8481
  7.8687

and then y can be found out very easily
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2015-06-21T14:54:45+05:30

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
 \sqrt{x} + y=7
y=7- \sqrt{x}
Putting y as 7-√x from eqn.(1) into eqn (2) we get:
x+ \sqrt{7- \sqrt{x} } =11
 (x+ \sqrt{7- \sqrt{x})^{2}=121
Let 7-√x be b.
(x+ \sqrt{b} )^{2} =121
 x^{2} +2 \sqrt{b}x+b=121.
Solving this equation gives x=9 and 
81+18√b+b=121
⇒√b(18+√b)=40
Now solve and find out √b.
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