# Calculate the final velocity when a body moves from rest & attains an acceleration of 5m/sec² covering a distance of 50 meters

2
by manman
fast frens i wantans.

• Brainly User
2014-05-25T16:39:34+05:30
calculate the final velocity when a body moves from rest & attains an acceleration of 5m/sec² covering a distance of 50 meters

Solution :

Initially body is at rest , hence initial velocity is Zero .
Acceleration = 5 m / sec^2
Distance traveled =  50 meters.
We Know that
V² - U² = 2as
Where V = final velocity  ,
U = initial velocity
a = Acceleration of the body
s= Distance Covered

V² - 0² = 2*5*50
V² = 500
V = √(500)
V = 10√5
Hence the Final Velocity of the body is 10√5 .

HOpe this helps You!!!

2014-05-25T18:01:09+05:30
TO find final velocity:

Given- distance- 50 meters
acceleration-5m/s
initial velocity(u)-0

the formula is v^2-u^2=2as

So, v^2-u^2=2as

v^-0=2*5*50
v^-0=500
v=500^
so square root of 500 is 22.360
so the Final velocity(v) is 22.360

the correct ans is
v=u+at v=20+2.10 v=20+20 v=40m/sec.
thank u sindhoora andgashu for your ans.