# Calculate the final velocity when a body moves from rest & attains an acceleration of 5m/sec² covering a distance of 50 meters

2
by manman

fast frens i wantans.

Log in to add a comment

by manman

fast frens i wantans.

Log in to add a comment

Solution :

Initially body is at rest , hence initial velocity is

Distance traveled = 50 meters.

We Know that

V² - U² = 2as

Where V = final velocity ,

U = initial velocity

a = Acceleration of the body

s= Distance Covered

V² - 0² = 2*5*50

V² = 500

V = √(500)

V = 10√5

Hence the Final Velocity of the body is 10√5 .

HOpe this helps You!!!

Given- distance- 50 meters

acceleration-5m/s

initial velocity(u)-0

the formula is v^2-u^2=2as

So,

v^-0=2*5*50

v^-0=500

v=500^

so square root of 500 is 22.360

so the Final velocity(v) is 22.360