Answers

2015-06-27T15:10:42+05:30
Let the number of sweets he had at start be x.
⇒Sweets given to Renu= \frac{x}{4}
⇒Sweets given to Raji=5
Given,
x- \frac{x}{4} -5=7
4x-x-20=28
3x=28+20
x= \frac{48}{3} =16
Ans: Sekhar had 16 sweets at start.

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