Answers

2015-06-27T19:26:22+05:30
(x^7) - (1/x^5)
=x(x^6 - 1/x^6)
=x[(x^3)^2 - [(1/x^3)^2]
=x(x^3 + 1/x^3)(x^3 - 1/x^3)
=x(x+1/x)(x^2 -1 +1/x^2)(x-1/x)(x^2 +1 +1/x^2)
=x(x+1/x)(x-1/x)(x^2 -1 +1/x^2)(x^2 +1 +1/x^2)    .....[Ans.]
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