#
Seven times a two digit number is equal to 4 times the number obtained by reversing the order of the digits and the sum of the digit is 3 find the number.

2
by sanyu

...

Log in to add a comment

by sanyu

...

Log in to add a comment

then the number is (10x + y)

x + y = 3 -------------------------(1) (given)

7(10x + y) = 4(10y + x) (given)

2x = y

put the value of y in equation (1)

3x = 3

x = 1

y = 2

hence number is (10*1 + 2) = 12

The Brainliest Answer!

Solution :

let the digit at units place = x

and the digit at tens place = y

therefore original number = 10y +x

reversed Number = 10x+y

According to question ,

7 (10y +x) = 4 (10x+y) ............(given)

70y + 7x = 40x +4y

70y - 4y = 40x - 7x

66y = 33x

2y = x

Sum of digits of two digit number = 3 ........(given)

x + y = 3

Substitute x in above equation , we get

2y + y = 3

3y =3

y= 3/3

substitute y in 1 , we get

x=2*1

Hence original number = 10y+x

= 10*1 + 2

= 10 + 2

= 12

hope this helps you!!!