# Seven times a two digit number is equal to 4 times the number obtained by reversing the order of the digits and the sum of the digit is 3 find the number.

2
by sanyu

2014-05-28T11:15:11+05:30
Let first digit is x & second digit is y.
then the number is (10x + y)
x + y = 3     -------------------------(1)      (given)
7(10x + y) = 4(10y + x)           (given)
2x = y
put the value of y in equation (1)
3x = 3
x = 1
y = 2
hence number is (10*1 + 2) = 12
• Brainly User
2014-05-28T12:49:26+05:30
seven times a two digit number is equal to 4 times the number obtained by reversing the order of the digits and the sum of the digit is 3 find the number.
Solution :
let the digit at units place = x
and the digit at tens place = y
therefore original number = 10y +x
reversed Number = 10x+y
According to question ,
7 (10y +x) = 4 (10x+y) ............(given)
70y + 7x = 40x +4y
70y - 4y = 40x - 7x
66y = 33x
2y = x
x =2y   ...............(1)

Sum of digits of two digit number = 3 ........(given)
x + y = 3
Substitute x in above equation , we get
2y + y  = 3
3y =3
y= 3/3
y=1
substitute y in 1 , we get
x=2*1
x=2

Hence original number = 10y+x
= 10*1 + 2
= 10 + 2
= 12

hope this helps you!!!

Thank You !!! :)