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2015-08-08T00:53:15+05:30

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X = (31.21)²×(.0123)³÷√.1×(15.2)²
           I assumed that  15.2 square is in the numerator... In case it is in the denominator, then subtract its logarithm...instead of  adding that..

     we use the principles  Log x^a  = a Log x
                                 and  Log X*Y = Log X + Log Y
Log 10 = 1        log 1/a = - log a

now  Log X
  = 2 Log 31.21 + 3 Log 0.0123 -  Log √0.1  + 2 Log15.2
  = 2 (Log 3.121 + log 10) + 3 (log 4.1 + log 3 - Log 1000) - 1/2 (-log 10) + 2 * (Log 1.9 +3 * Log 2)
  = 2 (1.4943) + 3 (-1.9100) + 1/2 + 2 (1.1818)
  =0.12199

now we do anti log  of  0.1299
X = 10^0.1299 = 1.3243

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