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## Answers

*Let us assume that √5 is a rational number.*

*we know that the rational numbers are in the form of p/q form where p,q are intezers.*

*so, √5 = p/q*

*p = √5q*

*we know that 'p' is a rational number. so √5 q must be rational since it equals to p*

*but it doesnt occurs with √5 since its not an intezer*

*therefore, p =/= √5q*

*this contradicts the fact that √5 is an irrational number*

*hence our assumption is wrong and √5 is an irrational number.*

__hope it helped u :)__√5= a/b where a and b are co prime

b=√5a

b²=5a²

so ,5 divides b

b=5c

b²=25c²

5a²=25c²

a²=5c²

so , 5 divides a

this contadicts the fact that a and b are co prime

so √5 is irrational