Answers

2015-07-05T14:04:45+05:30
Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are intezers.
so, √5 = p/q
     p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesnt occurs with √5 since its not an intezer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.



hope it helped u :)
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2015-07-05T14:13:09+05:30
Assume that √5 is irrational  such that 
√5= a/b  where a and b are co prime 
b=√5a
b²=5a²
so ,5 divides b 
b=5c
b²=25c²
5a²=25c²
a²=5c²
so , 5 divides a 
this contadicts the fact that a and b are co prime  
so √5 is irrational 
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