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## Answers

For this Problem we will use an Identity that,

(x+a) (x+b) = x²+x(a+b) + ab.

Now we can write 105 as (100+5) and also 97 as (100-3).

Therefore here,

x= 100, a= 5 and b= -3

now by putting these values in the above Algebraic Identity we get,

{100+5} {100+(-3)} = 100²+100(5-3)+5×(-3)

= 10000+500-300-15

= 10185

Hence, 105×97 = 10185