# 20 boys and girls sold tickets for a funfair. Each ticket was sold at $5.Each boy sold 5 tickets and each girl sold 3 tickets. The amount collected by the boys was$20 more than the amount collected by the girls. Find a) how many girls were there in the group b) how many tickets were sold altogether?

1
by SnehaPatel458

• Brainly User
2014-05-29T15:02:14+05:30
20 boys and girls sold tickets for a funfair. Each ticket was sold at $5.Each boy sold 5 tickets and each girl sold 3 tickets. The amount collected by the boys was$20 more than the amount collected by the girls. Find

a) how many girls were there in the group
b) how many tickets were sold altogether?

Solution:
No Of Boys = 20
Let No Of Girls = x
No. Of Tickets sold by One Boy  = 5
Therefore Number of tickets Sold by 20 Boys = 5*20
= 100
Cost of one Ticket = $5 therefore Cost of 100 Tickets =$5*100
= $500 No. Of tickets Sold by One Girl = 3 Therefore , No of tickets Sold By x Girls = 3*x = 3x Therefore Cost of 3x tickets =$5*3x
= $15x According to Problem ,$15x = $500 -$20
$15x=$480
x=$480/$15
x= 32
Hence The Number of Girls is 32 .

b) therefore total Number of Tickets sold = 100 + 3x
= 100 + 3*32
= 100 + 96
=196
Hope This Helps You!!!