20 boys and girls sold tickets for a funfair. Each ticket was sold
at $5.Each boy sold 5 tickets and each girl sold 3 tickets. The amount
collected by the boys was $20 more than the amount collected by the
girls. Find

a) how many girls were there in the group

b) how many tickets were sold altogether?

Solution:

No Of Boys = 20

Let No Of Girls = x

No. Of Tickets sold by One Boy = 5

Therefore Number of tickets Sold by 20 Boys = 5*20

= 100

Cost of one Ticket = $5

**therefore Cost of 100 Tickets = $5*100**

** = $500**

No. Of tickets Sold by One Girl = 3

Therefore , No of tickets Sold By x Girls = 3*x

= 3x

** Therefore Cost of 3x tickets = $5*3x**

** = $15x**

According to Problem ,

$15x = $500 - $20

$15x= $480

x=$480/$15

x= 32

**Hence The Number of Girls is 32 **.

b) therefore total Number of Tickets sold = 100 + 3x

= 100 + 3*32

= 100 + 96

=196

Hope This Helps You!!!