Answers

2014-05-31T15:42:30+05:30
LET theta be Ф & NUMBERS THAT ARE UNDERLINED ARE SOLVED IN NEXT LINE.

QUESTION: tan(90-Ф)cotФ - sec(90-Ф) cosecФ +3(cot² 67 - sec² 63) / cot 26 cot 41 cot 45                     cot 49 cot 64

SOLUTION: cotФ cotФ - cosecФ cosecФ +3(cot² 67 - sec² 63) / cot(90 - 64) cot(90 -49)                          cot 45 cot 49 cot 64

                  cot²Ф - cosec²Ф + 3(cot² 67 - sec² 63) / tan 64 cot64 *1*cot 49 tan 49

                  -1 +3(cot² 67 - sec² 63) / 1*1*!

                  -1 +3(cot² 67 - sec² 63 )

                  -1 +3cot² 67 - 3sec² 63

**//THIS QUESTION CAN NOT BE FURTHER SOLVED.THE VALUE 67 OR 63 MUST BE CHANGED OTHERWISE IT CAN NOT BE SOLVED//**
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