Answers

2014-05-30T14:52:12+05:30
Intersection point of curve is 
x² = (x-2)² 
x² = x² + 4 - 4x
x =1 
put x = 1 in first curve 
y = 1
hence point = (1,1)
y = x²---------(1)
y = (x -2)² -------------(2)
dy/dx = 2x 
dy/dx = 2    let m1                (at point (1,1))
dy/dx = 2(x-2)
dy/dx = -2   let m2              (at point (1,1))
tan Ф = (m1 - m2)/(1 + m1*m2)        (Ф = angle between curves at point of intersection)
tan Ф = 4/ -3
Ф = tan^-1(-4/3)
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