Answers

2015-07-09T11:15:27+05:30
The line has a slope m
3x+2y=13;
2y=13-3x
y=13/2-3x/2
therefore m=-3/2
therefore slope of perpendicular(m1) =1/(-m)
m1=2/3
eq of perp=3y-2x=0;
Solving this we get
x=9/2;    y=-3
0