# Suppose ABCD is a parallelogram in which angle A = 108'. Calculate angles B, C and D.

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In parallelogram ABCD

m/_A=108·

m/_C=m/_A=108· (opposite angle of a parallelogram are congruent)

m/_A+m/_B=180 (adjacent angle of a parallelogram are congruent)

108+m/_B=180

m/_B=180-108

m/_B=72

m/_B=m/_D=72 (opposite angle of a parallelogram are congruent)

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Consider a,b,c,d to be the vertices of the parallelogram taken in cyclic order.

A = 108 degree

opposite sides are equal

C = 108 degree

base angles are supplementary

A+B = 180

B =180-108=72

B and D are opposite . Hence D = 72 degree

A = 108 degree

opposite sides are equal

C = 108 degree

base angles are supplementary

A+B = 180

B =180-108=72

B and D are opposite . Hence D = 72 degree