# the resultant resistance of two resistance wires in series combination is 108 ohm and in parallel combination is 24 ohm. find the value of individual resistance

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by deepesh08

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by deepesh08

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The Brainliest Answer!

Solution:

Let the resistances of two wires be r1 and r2 .

According to Question ,

Equivalent Series resistance = 108

Equivalent Parallel resistance = 24

or 24 (r1+r2) = r1r2

24(108) = r1r2

2592 = r1r2

or

or r1 = 2592 /r2 ....................... (2)

2592 +r2² =108r2

r2² - 108r2 +2592 = 0

here a=1 , b= -108 and c= 2592

d = -b +-√(b² - 4ac)/2a

=108 +-√(11664 - 10368 ) / 2*1

=108 +-√1296 / 2

=108+-36 /2

= 108+36 / 2 or 108-36/2

= 142 /2 or 72/2

= 71 or 36

Let me take it as 36

hence r2 = 36

Substitute r2 = 36 in equation 1 , we get

r1 = 108 - 36

r1 = 72

Hence the two resistance are 36 and 72 !!

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