Let the two positive numbers be x and y.
xy = 64
⇒ y = 64/x
Sum, s = x+y = x + (64/x)
now, we have to minimise s.
For s to be minimum, two condition should be satisfied:
Now for second condition,
So, at x=8, the sum is minimum.
y = 64/8 = 8So the numbers are (8,8)